In a city school, 60% of students have blue eyes, 55% have dark hair, and 35% have blue eyes and dark hair. what is the probability (rounded to the nearest whole percent) that a randomly selected student has dark hair, given that the student has blue eyes?

60% have blue eyes.

35% have blue eyes and dark hair.

Divide the percent that has both blue eyes and dark hair by the percent who have blue eyes:

35 / 60 = reduces to 7/12 = 58.3% have dark hair given they have blue eyes.

3= 3 ticks above 0

2.25= 2.25 ticks above 0

opposite of 4= 4 ticks below 0

-(-1 1/2)= 1.5 ticks above 0

<| - - - | - - - | - - - | - - - | - - - | - - - | - - - | - - - |>

- 4 0 1.5 2.25 3

-4 = 5.5 ticks below 1.5; 6.25 ticks below 2.25; 7 ticks below 3

1.5= 5.5 ticks above -4; 0.75 ticks below 2.25; 1.5 ticks below 3

2.25= 6.25 ticks above -4; 0.75 ticks above 1.5; 0.75 ticks below 3

3= 7 ticks above -4; 1.5 ticks above 1.5; 0.75 ticks above 2.25