In a company, it takes 4 employees 4 days to complete a task. it would take 2 employees 8 days to complete the same task.

(1) In one day eight workers do 1/121/12-th of the total work, so each workers does

1128=196- th of the work each day1128=196- th of the work each day

(2) Four workers thus do

4196=124−- th of the work each day4196=124−- th of the work each day

so how many days do they need to finish the work?

The above is the general setting for these problems. In the present case there is, of course, a much simpler approach: 44 workers will finish the work in twice the time as 88 workers...

I wanna say the answer is(1) In one day eight workers do 1/121/12-th of the total work, so each workers does

1128=196- th of the work each day1128=196- th of the work each day

(2) Four workers thus do

4196=124−- th of the work each day4196=124−- th of the work each day

so how many days do they need to finish the work?

The above is the general setting for these problems. In the present case there is, of course, a much simpler approach: 44 workers will finish the work in twice the time as 88 workers...

ML of water equals 1 cm^3 of volume so the answer will be 1.72^3