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mswillm
24.12.2020 •
Mathematics
In a large city, 82% of residents own a cell phone. Suppose that we randomly select three city residents. What is the probability that at least one of the three residents does not own a cell phone
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Ответ:
P(X≥1) = 0.45 (approximately)
Step-by-step explanation:
Let X be a random variable, then X follows a binomial distribution with probability of success, p and number trials, n.
The probability distribution is given as:
P(X) = nCx * p^x * (1 – p)^(n – x)
Where p is Probability of success, n is number of trials and x is total number of successes.
Probability of having phone is 82% = 0.82
Probability of not having phone is 100% – 82% = 0.18.
Since the trials are interested in those that are not having phone, then probability of success, p = 0.18.
Number of trials, n = 3.
P(X ≥ 1) = 1 – P(X < 1) = 1 – P(X = 0)
P(X = 0) = 3C0 * (0.18)^0 * (0.82)^(3) = 1 * 1 * 0.551368 = 0.551368
P(X ≥ 1) = 1 – 0.551368 = 0.448632 ≈ 0.45
Ответ:
yes
Step-by-step explanation: