Mathematics: In a poll of 555 randomly selected students, 40% stated that they enjoyed statisticsa. Identify the number of students who say that they enjoy statistics? Round to the nearest whole student if necessary.b. Construct a 95% confidence interval estimate of the percentage of all students who say that they enjoy statistics.c. Can we safely conclude that majority of students enjoy statistics? Explain.

X=2.8 when y =14 Step-by-step explanation:...

In a poll of 555 randomly selected students,

iritike3347

01.02.2022

N = 222

0.36< p

No we can not safely conclude that majority of students enjoy statistics because the upper limit of the confidence level is less than 50%

Step-by-step explanation:

From the question we are told that

The sample size is n = 555

The percentage that enjoyed statistics is $\r p = 40% = 0.40$

Generally the number of student who say they enjoyed statistics is mathematically represented as

N = 0.40 * 55

=> N = 222

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = ( 100-95)\%$

=> $\alpha = 0.05$

The critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is $Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{ \r p (1 - \r p )}{n} }$

=> $E = 1.96 * \sqrt{ \frac{0.40 (1- 0.40 )}{ 555} }$

=>. E = 0.04

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

=> 0.40 - 0.04 < p

=> 0.36< p

No we can not safely conclude that majority of students enjoy statistics because the upper limit of the confidence level is less than 50%

0,0(0 оценок)