Mathematics: In a random sample of five mobile devices, the mean repair cost was $90.00 and the standard deviation was $14.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results.The 95 % confidence interval for the population mean is (Round to two decimal places as needed.) The margin of error is (Round to two decimal places as needed.) Interpret the results. Choose the correct

In a random sample of five mobile devices, the

numb2000

26.01.2022

The correct option is;

B. With 95 percent confidence, it can be said that the repair cost is between the bounds of the confidence interval

Step-by-step explanation:

Here we have the formula for confidence interval, CI given as follows;

$CI=\bar{x}\pm t\frac{s}{\sqrt{n}}$

Where:

$\bar x$ = Sample mean = $90.00

s = Sample standard deviation = $14.00

n = Sample size = 5

t = z value for the confidence level = 2.7764 from z-score relations

Plugging in the values, we have;

$CI=90.00\pm 2.7764 \frac{14.00}{\sqrt{5}}$

Which gives the CI as 72.6167 to 107.38.

0,0(0 оценок)

s855753

03.12.2020

sin theta = 3 sqrt(21)/17

Step-by-step explanation:

cos theta = adj / hyp

We can find the opp by using the Pythagorean theorem

adj^2 + opp ^2 = hyp^2

10^2 +opp^2 = 17^2

100 + opp^2 = 289

opp^2 = 289-100

opp^2 = 189

Taking the square root

opp = sqrt(189)

opp = 3 sqrt(21)

Since we are in the first quad, opp is positive

sin theta = opp /hyp

sin theta = 3 sqrt(21)/17

0,0(0 оценок)