remyboy1938
18.11.2020 •
Mathematics
In a rectangle, the length is 7 m less than three times the width and the area is 111 m. Approximate the dimensions to the nearest tenth of a meter.
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Ответ:
The dimensions are 7.4m by 15.1 m (to the nearest tenth).
Step-by-step explanation:
Area = length * width
If the width = x then the length = 3x - 7 so
Area x(3x - 7) = 111
3x^2 - 7x - 111 = 0
Using the quadratic formula:
x = [ -(-7) +/- √((-7)^2 - 4*3*-111)] / (2*3)
x = 7.36, -5.03.
The width must be positive s it is 7.36 m.
The length = 3(7.36) - 7
= 15.08 m.
Ответ:
m + 5 = 4m – 10
Step-by-step explanation:
I cant write slope intercept form on sorry