Mathematics: In a series rl circuit, et = 120 v, r = 40 ω, and xl = 30 ω. how much is el?

In a series rl circuit, et = 120 v, r = 40 ω, - id12040526158, nathaliapachon7948

xaviercarrasco04

30.09.2020

Firstly, we will draw

RL series circuit

ET = 120 V, R = 40 Ω, and XL = 30 Ω

Firstly, we will find current

$I=\frac{E_T}{R+jX_L}$

now, we can plug values

and we get

$I=\frac{120}{40+j30}$

now, we can find voltage across L

E_L=IjX_L

so, we get

$E_L=\frac{120}{40+j30}(j30)$

now, we can find absolute value

$|E_L|=120\frac{30}{\sqrt{40^2+30^2} }$

$|E_L|=120\frac{30}{ 50 }$

$|E_L|=120\frac{3}{ 5 }$

|E_L|=72V ...............Answer

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marco34perez

14.01.2022

Chips: 1.25 and Sandwiches: 6.5

Step-by-step explanation:

3s+2c=22

2s+c=14.25

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