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31.05.2021 •
Mathematics
In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.
a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?
b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.
c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.
d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.
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Ответ:
a) The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.
b) The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.
c) The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).
d) The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
Standard error:
The standard error is:
Margin of error:
The margin of error is:
The confidence interval is:
Sample proportion plus/minus margin of error. So
In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.
This means that![n = 1500, \pi = \frac{1305}{1500} = 0.87](/tpl/images/1356/3663/d649e.png)
a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?
0.0087*100% = 0.87%.
The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.
b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
Then
0.0171*100% = 1.71%
The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.
c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.
87% - 1.71% = 85.29%
87% + 1.71% = 88.71%.
The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).
d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.
The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.
Ответ:
4inch x 7inch = 16 x 28 = 448 sqft
Step-by-step explanation: