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janai3602
22.01.2020 •
Mathematics
In a study of plant safety, it was found that the time it took for machine operators to react to a warning light was normally distributed with a mean 1 second and standard deviation 0.3 second. suppose a warning light visible to 4 operators goes on. what is the probability that the average (mean) reaction time of the 4 operators exceeds 1.25 seconds?
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Ответ:
4.75% probability that the average (mean) reaction time of the 4 operators exceeds 1.25 seconds.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation ![\frac{\sigma}{\sqrt{n}}](/tpl/images/0464/9775/0c6ba.png)
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that the average (mean) reaction time of the 4 operators exceeds 1.25 seconds?
This is 1 subtracted by the pvalue of Z when X = 1.25. So
So there is a 1-0.9525 = 0.0475 = 4.75% probability that the average (mean) reaction time of the 4 operators exceeds 1.25 seconds.
Ответ: