In ∆abc, ab is extended through d, m< cbd =30 and ab = bc. what is the measure of angle a

15°

Step-by-step explanation:

∠ABC and ∠DBC form a straight angle and are supplementary, thus

∠ABC + 30 = 180 ( subtract 30 from both sides )

∠ABC = 150°

Since AB = BC then ΔABC is isosceles with ∠BAC = ∠BCA

The sum of the 3 angles in the triangle = 180°

Hence ∠BAC = = = 15

That is ∠a = 15°

0.98

Step-by-step explanation:

0.982,0.98()2 (round up if 5+ down 4-) 0.98