In △ABC, m∠CAB = 60°, AD
is the angle bisector of ∠BAC with D ∈
BC
and AD = 8ft. Find the distances from point D to the sides of the triangle.

The answer is 4

Step-by-step explanation:

if you want a step-by-step explanation, you can click on the link here

Step-by-step explanation:

Hey there!

Here;

Given is; angle AEB = 88°

angle AEB + angle AED = 180° { being linear pair}

88° + angle AED = 180°

angle AED = 180° - 88°

Therefore, angle AED = 92°

Therefore, answer is Option C.

Hope it helps...