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wirchakethan23
11.03.2021 •
Mathematics
In ΔABC, the measure of ∠C=90°, the measure of ∠A=39°, and BC = 9.7 feet. Find the length of AB to the nearest tenth of a foot. (please answer correctly I will give brainliest)
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Ответ:
15.4 ft
Step-by-step explanation:
\sin A = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{9.7}{x}
sinA=
hypotenuse
opposite
=
x
9.7
\sin 39=\frac{9.7}{x}
sin39=
x
9.7
x\sin 39=9.7
xsin39=9.7
Cross multiply.
\frac{x\sin 39}{\sin 39}=\frac{9.7}{\sin 39}
sin39
xsin39
=
sin39
9.7
Divide each side by sin 39.
x=\frac{9.7}{\sin 39}=15.4135\approx 15.4\text{ feet}
x=
sin39
9.7
=15.4135≈15.4 feet
Type into calculator and round to the nearest tenth of a foot.
Ответ:
2
Step-by-step explanation: