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michelemosbahiow6yya
11.02.2020 •
Mathematics
In an effort to estimate the mean amount spent per customer for dinner at major Atlanta restaurant, data were collected for a sample of 49 customers over a period of three weeks. Assume a population standard deviation of $2.50. If the sample mean is $22.60, compute a 98% confidence interval for population mean?
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Ответ:
Confidence Interval is (21.76928571,23.43071429)
Step-by-step explanation:
The Formula we are going to use is:
Where:
μ is the mean of sample
σ is the standard deviation of population
n is the sample size
z is the distribution
In our case:
μ=$22.60,σ=$2.50
For 98% Confidence level, 1-α=98%
α=2%
α/2=1%=0.01
From Cumulative standardized Normal Distribution table
P=23.430714 P=21.769286
Confidence Interval is (21.76928571,23.43071429)
Ответ:
there equal
Step-by-step explanation:
-x = -1
so that would mean
-1 < -1
which means there equal