In circle a below, ∠bae ≅ ∠dac. circle with center a and points b, c, d, e are labeled counterclockwise. angle bae and angle dac are marked congruent. arc be is labeled 12 x minus 10 degrees and arc dc is labeled 5 x plus 53 degrees. what is the marc bcd? a. 82° b. 98° c. 164° d. 180°

We have that the 2 arcs need to be equal, because their angles are the same. Hence, we get by setting the two expressions equal:
12x-10=5x+53 or 12x-5x=53+10 or 7x=63 or x=9. Hence, arce BE is equal to 12x-10=12*9-10=98 degrees.
This is also equal to the arc DC. Since we have calculated arc DC, we only need to calculate arc BD (and sum those two). The total arcs of a circle are 360 degrees.
Hence, EB+BC+DC+CE=360. But we have that BC+CE. So, we get:
98+BC+98+BC=360. Hence, we get that BC=CE(360-2*98)/2=82 degrees. Hence, BCD=98+82=180 degrees.

so... the answer is???

To find the median, place the numbers in order from least to greatest then find the number in the middle

0.6, 0.87, (0.87, 1.1), 1.23, 2

0.87 and 1.1 are in the center.

Add 0.87 to 1.1 then divide it by 2

0.87 + 1.1 = 1.97

Half of 1.97 is 0.985

Hope this helps