In how many ways can a full house of three jacks and a pair of twos be obtained from an ordinary deck of cards

24 ways

Step-by-step explanation:

A standard deck of cards contains 4 house of Jack's.

Thus, number of ways a full house of three jacks can be selected is;

4C3 = 4!/(1! × 3!) = 4

In a standard deck of cards, there are 4 houses of twos.

Thus, number of ways to select a pair is;4!/(2! × 2!) = 6

Now, combined number of ways to select a full house of three jacks and a pair of twos = 4 × 6 = 24

B = ( -3 , 2)

Step-by-step explanation:

You would use a mid point formular because you are trying to find the middle of a line . The midpoint formular is (X1 + X2 , Y1 + Y2 )  

                                                                 /2            /2

From the information given A is (7 , -2 )

If you fill it in it would be 7 + X , -2 + X

                                         /2         /2           =   (2 , 0 )

The only posible solution would be 7- 3 /2  , -2 + 2 / 2

Makeing B (-3, 2).