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fredvales19
17.04.2021 •
Mathematics
In ijk,i=170 inches,j=119 and k=42.find the area of ijk,to the nearest square inch
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Ответ:
9514 1404 393
25,975 in²
Step-by-step explanation:
Since your j+k < i, we assume that not all of these dimensions are side lengths. If we assume ...
i = 170 in
J = 119°
K = 42°
Then we can find side j using the law of sines.
I = 180° -119° -42° = 19°
Then the law of sines tells us ...
j/sin(J) = i/sin(I)
j = i·sin(J)/sin(I) = (170 in)sin(119°)/sin(19°) = 456.695
Then the area of the triangle is ...
A = (1/2)(i·j·sin(K)) = (1/2)(170 in)(456.695 in)sin(42°) ≈ 25,975.03 in²
The area of triangle IJK is about 25,975 square inches.
Ответ:
The second one