Mathematics: In need of help on Alg 2

270+3s =540. i did the math and I m pretty sure this is the correct answer...

In need of help on Alg 2 - id211601841, Jbutler15

musicalmel

02.03.2021

$\frac{20}{13}$ + $\frac{5}{13}$ $\sqrt{3}$

Step-by-step explanation:

Given

$\frac{5}{4-\sqrt{3} }$

To rationalise the denominator, multiply the numerator/ denominator by the conjugate of the denominator.

The conjugate of 4 - $\sqrt{3}$ is 4 + $\sqrt{3}$

= $\frac{5(4+\sqrt{3}) }{(4-\sqrt{3})(4+\sqrt{3}) }$

= $\frac{20+5\sqrt{3} }{16-3}$

= $\frac{20+5\sqrt{3} }{13}$

= $\frac{20}{13}$ + $\frac{5}{13}$ $\sqrt{3}$

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