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janetexcoelho
18.03.2021 •
Mathematics
In ΔOPQ, o = 58 cm, q = 13 cm and ∠Q=52°. Find all possible values of ∠O, to the nearest degree.
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Ответ:
There is no possible triangles
Step-by-step explanation:
\frac{\sin A}{a}=\frac{\sin B}{b}
a
sinA
=
b
sinB
From the reference sheet (reciprocal version).
\frac{\sin O}{58}=\frac{\sin 52}{13}
58
sinO
=
13
sin52
Plug in values.
\sin O=\frac{58\sin 52}{13}\approx 3.5157403
sinO=
13
58sin52
≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}
O=sin
−1
(3.5157403)=ERROR
Sine cannot be greater than 1.
{No Possible Triangles}
No Possible Triangles
{}
{}
Ответ:
9,32 . 7,16 . 3,8 . 5,8 . 3,4 . 1,2
in that order buddy make it exactly like this :)