Mathematics: In parallelogram defg, dh = x + 1, hf = 3y, gh=3x−4,and he = 5y + 1. find the values of x and y. the diagram is not drawn to scale

In parallelogram defg, dh = x + 1, hf = 3y, gh=3x−4,and

cierramcdonald

10.03.2022

ANSWER

$x = 5 \: and \: = 2$

EXPLANATION

The diagonals of a parallelogram bisects each other.

Therefore

DH=HF

This implies that,

x + 1 = 3y

We make x the subject to get,

x = 3y - 1...eqn1

Similarly,

GH=HE

This implies that,

3x - 5y = 5...eqn2

We substitute equation (1) in to equation (2) to get,

3(3y - 1) - 5y = 5

We expand the bracket to get,

9y - 3 - 5y = 5

We group like terms to get,

9y - 5y = 5 + 3

Divide both sides by 4 to obtain,

y = 2

We put the value of y into equation (3) to get,

x = 3(2) - 1

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aliyyahlove

03.12.2020

sorry this is is not answer for/p>

have a great day

Step-by-step explanation:

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