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22.02.2021 •
Mathematics
In parallelogram DEFG DH=x+2 HF=2y GH=3x-3 and HE=5y+1. Find the values of x and y.
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Ответ:
y = 10 and x =18
Step-by-step explanation:
From the parallelogram,
DH + HF = DF
x+2 + 2y = DF
Also DH = HF
x+2 = 2y
x - 2y = -2 1
Also GH = HE
3x-3 = 5y+1
3x - 5y = 1 + 3
3x-5y = 4 2
Solve 1 and 2 simultaneously
x - 2y = -2 1 * 3
3x-5y = 4 2 * 1
3x-6y = -6
3x-5y = 4
Subtract
-6y + 5y = -6-4
-y = -10
y = 10
Substitute y = 10 into 1
x- 2y = -2
x - 2(10) = -2
x - 20 = -2
x = -2+20
x = 18
Hence y = 10 and x =18
Ответ:
true
Step-by-step explanation: