In the figure below, m2 1=106º. Find m2, mZ3, and m2 4

1 = 106

2 = 74

3 = 106

4 = 74

Step-by-step explanation:

Vertical angles congruent and supplementry angles theorm

∠2 = 74º

∠3 = 106º

∠4 = 74º

Step-by-step explanation:

∠2 is supplementary to ∠1

∠2 = 180 - 106

∠2 = 74º

∠3 is a vertical angle to ∠1

∠3 = ∠1

∠3 = 106º

∠4  is a vertical angle to ∠2

∠4 = ∠2

∠4 = 74º

A= (3√6 * 6√2) ÷ 2 = 18√3

Step-by-step explanation:

Area= PQ/2

P and Q are the diagonals(  inside of the kite) lines

Q diagonal  q^2= (3√2)^2+6^2

                           18+36 =54

q=√54 = 3√6

p=√72 =6√2