In the figure. d=4 yd, h=6 yd, and h=8 yd. what - id4682459482, wereallmadhere111

Ответ:

asiababbie33

03.01.2022

Check the picture below.

so is really just a cylinder with a cone on the side, notice, since the diameter of the base is 4, the radius is half that then.

so we just simply get the volume of the cylinder, and the cone, and sum them up

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=2\\
h=6
\end{cases}\implies V=\pi \cdot 2^2\cdot 6\\\\
-------------------------------\\\\
\textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=2\\
h=2
\end{cases}\implies V=\cfrac{\pi \cdot 2^2\cdot 2}{3}\\\\
-------------------------------\\\\
\stackrel{cylinder's~volume}{24\pi }~~+~~\stackrel{cone's~volume}{\cfrac{8\pi }{3}}$

In the figure. d=4 yd, h=6 yd, and h=8 yd. what is the approximate volume of the figure? use 3.14 t

In the figure. d=4 yd, h=6 yd, and h=8 yd. what is the approximate volume of the figure? use 3.14 t

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In the figure. d=4 yd, h=6 yd, and h=8 yd. what is the approximate volume of the figure? use 3.14 to approximate

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