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mairadua14
16.11.2019 •
Mathematics
In the game of blackjack played with one deck, a player is initially dealt 2 diferent cards from the 52 different cards in the deck a winning ℡ack ack hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. the two cards can be in any order. find the probability of being dealt a blackjack hand. what approximate percentage of hands are winning blackjack hands?
the probability is □ type an integer or a simplified fraction)
the percentage of hands that are winning blackjack hands is round to two decimal places as needed.)
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Ответ:
4.83%
Step-by-step explanation:
Total number of possible hands
we are interested in selecting two of the 52 cards in the deck.
n=52
r=2
therefore,
52C_2 = 52!/(2!50!)= 1326 possible hands
therefore total number of blackjacks
A blackjack consists of 1 of 4 aces and 1 of 16 other cards that are worth 10 points.
by fundamental counting rule
4*16= 64 possible blackjacks
2)% of hands that are winning blackjack hands =(32/663)*100 =4.83%
Ответ:
45 ÷ 3
24 ÷ 3
= 15/8
= 1 7/8