In the general population, what is the probability that an individual will have the birth defect, assuming that maternal and paternal genes

0.0625

Step-by-step explanation:

The prevalence of gene a = 25 %, P (a) = 0.25

birth defect occurs when both parents have prevalence of gene a.

P (Defect) = P ( Both parents have gene a)

If both parents inherit the gene a independently, the the individual will have a birth defect when both parents have gene a.

P ( Father having gene a) = 0.25

P ( Mother having gene a) = 0.25

Hence,

P (Birth Defect) = P ( Both parents have gene a) = 0.25 * 0.25 = 0.0625

First:

8 out of 25 students are boys.
Put that in fraction form

8/25

Now..

Turn that 25 into 100
So

8/25 = 32/100

25/25 is 100%
So
25/25 = 100/100

100/100 - 32/100 = 68/100

So 68% of the students are girls.
Hope this helps! :D