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tay9625
01.07.2019 •
Mathematics
In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x, y, z) is evaluated at the center (xi, yj, zk) of the box bijk. use the midpoint rule to estimate the value of the integral. divide b into eight sub-boxes of equal size. (round your answer to three decimal places.)triple integrals of cos(xyz) dv,where b = {(x, y, z) | 0 ≤ x ≤ 2, 0 ≤ y ≤ 2, 0 ≤ z ≤ 2}
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Ответ:
To approximate the volume with 8 boxes, we have to split up the interval of integration for each variable into 2 subintervals, [0, 1] and [1, 2]. Each box will have midpoint
that is one of all the possible 3-tuples with coordinates either 1/2 or 3/2. That is, we're sampling
at the 8 points,
(1/2, 1/2, 1/2)
(1/2, 1/2, 3/2)
(1/2, 3/2, 1/2)
(3/2, 1/2, 1/2)
(1/2, 3/2, 3/2)
(3/2, 1/2, 3/2)
(3/2, 3/2, 1/2)
(3/2, 3/2, 3/2)
which are captured by the sequence
with each of
being either 1 or 2.
Then the integral of
over
is approximated by the Riemann sum,
(compare to the actual value of about 4.159)
Ответ: