In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took hour longer. How far did she travel to the appointment?
Select one:
A. 30 mi
B. 80 mi
C. 2 mi
D. 100 mi

25 miles

Step-by-step explanation:

Let t represent the time she spent in travelling to the appointment. The return trip took 1/8 hour longer.

It means that the time it took her to return is t + 1/8 = t + 0.125

Distance = speed × time

May drove to an appointment at 50 mph. It means that the distance she travelled on her way to the appointment is 50 × t = 50t miles

Her average speed on the return trip in the afternoon was 40 mph. It means that the distance she travelled on her way back is

40(t + 0.125) = 40t + 5

Since the distance travelled is the same, then

50t = 40t + 5

50t - 40t = 5

10t = 5

t = 5/10

t = 0.5 hour

Distance covered in travelling for the appointment is

50 × 0.5 = 25 miles

Given:

The equation is

To find:

The value of x.

Solution:

We have,

Isolating the variable, we get

Therefore, the value of x is 44.2.