jaylene33002
09.07.2019 •
Mathematics
In the xy-plane, if the parabola wiry equation y=ax^2+bx+c, where a, b, and c are constants, passes through the point (-1,1), which of the following must be true? a) a-b=1 b) -b+c=1 c) a+b+c=1 d) a-b+c=1 ; (
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Ответ:
again:a-b+c=1
Ответ:
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Form- 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalment