Mathematics: In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

X= 2 1/2 simplify it and you will get 5/2.Hope this helps. :-)...

In this diagram, bac~edf. if the area of bac= 6 in.²,

marisa2278

31.01.2022

2.7 in²

Step-by-step explanation:

Given:

∆BAC ~ ∆EDF

Area of BAC = 6 in²

EF = 2 in

BC = 3 in

Required:

Area of ∆EDF

SOLUTION:

Let x = area of ∆EDF

$\frac{6 in^2}{x} = (\frac{3 in}{2 in})^2$ (theorem of area of similar triangles)

$\frac{6 in^2}{x} = (\frac{3 in}{2 in})^2$

$\frac{6}{x} = \frac{9}{4}$

Cross multiply:

6*4 = 9*x

24 = 9x

Divide both sides by 9

$\frac{24}{9} = x$

2.67 = x

Area of ∆EDF = 2.7 in²

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