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schoolboyq3017
13.01.2021 •
Mathematics
In this triangle, the product of sin B and tan C is
and the product of sin Cand tan B is
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Ответ:
Step-by-step explanation:
sinB =
=
= ![\frac{b}{a}](/tpl/images/1031/9515/bd65f.png)
tanC =
=
= ![\frac{c}{b}](/tpl/images/1031/9515/23f9a.png)
Thus
sinB tanC =
×
( cancel b on numerator/ denominator )
=![\frac{c}{a}](/tpl/images/1031/9515/d37f6.png)
---------------------------------------------------------------------------
sinC =
=
= ![\frac{c}{a}](/tpl/images/1031/9515/d37f6.png)
tanB =
=
= ![\frac{b}{c}](/tpl/images/1031/9515/d30f8.png)
Thus
sinC tanB =
×
( cancel c on numerator/ denominator )
=![\frac{b}{a}](/tpl/images/1031/9515/bd65f.png)
Ответ:
i disagree i believe i recall it being the lower and upper quarters the lower is one wisker the box will be the 2 and 3 quarter and the other wisker will be the upper quarter