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sophiateaches053
17.06.2021 •
Mathematics
In this unit, you studied a handful of circle theorems. However, there are other circle theorems not covered in this unit or course. Do some research online or in textbooks to uncover a circle theorem (or more than one) that wasn’t presented in this unit. Describe it in detail. Then write either a two-column proof or a paragraph proof for the theorem. Does the theorem that you proved relate to theorems that you previously studied? If so, how? Were you able to apply some theorems that you proved earlier to your newfound theorem? Explain. How might your theorem be used in a real-world application?
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Ответ:
i researched online the alternate segment theorem and i found out that The alternate segment theorem (also known as the tangent-chord theorem) states that in any circle, the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.
Step-by-step explanation:
Ответ:
Hello Carousel!
![\huge \boxed{\mathbb{QUESTION} \downarrow}](/tpl/images/2521/7434/1e7eb.png)
Solve the integral.First, let's take I as ⇨
.
Let, x + 1 = m² => dx = 2mdm.
Now, divide the numerator & denominator by m²....we'll get it as...
Now, let m - 1/m be t => (1 + 1/m²) dm = dt
We know,
...therefore...
Now, substitute the value of 't' in eq. 1..we'll get..
Now, substitute the value of 'm' in eq. 2...we'll get...
![\tt \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{ \sqrt{x + 1} - \frac{1}{ \sqrt{x - 1} } }{ \sqrt{3} } ) + c \\ \tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x + 1 - 1}{ \sqrt{3} \sqrt{x - 1} } ) + c \\ \boxed{\boxed{ \bf \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x }{ \sqrt{3 (x - 1} )} ) + c }}](/tpl/images/2521/7434/e3968.png)
The correct answer is Option B.__________________
The question is really long & tricky but once you get the hang of it you'll be good. Good luck!__________________
Hope it'll help you!
ℓu¢αzz ッ