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kev71
20.09.2019 •
Mathematics
In triangle $abc$, $m\angle a = 90^\circ$, $m\angle b = 75^\circ$, and $bc = \sqrt {3}$ units. what is the area of triangle $abc$? express your answer as a common fraction. your answer submittips give up
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Ответ:
sin 75 = height / √3
height = 1.67
cos 75 = base / √3
base = 0.45
Area = bh/2
Area = (0.45) (1.67) / 2
Area = 0.37 square units
Therefore, the area of the triangle is about 0.37 square units.
Ответ: