Ineed solving question 56, 58 and 59.

56a. 3000(1+.06)^5= 4014.67
56b. 3000(1+(.06/2))^5= 3477.82
56c. 3000(1+(.06/12))^5= 3075.75
56d. 3000e^(0.06•5)= 4049.57

58a. When placed in a scientific calculator and finding the ExpReg, you get the equation 50•2.828^x, so you take 2.828 and turn that in to a percentage so it’ll be about 2.83%.
58b. 50
58c. 50•2.828^t
58d. 50•2.828^4.5= about 5,378 bacteria
58e. Putting the equation and 50,000 into a graphing calcultor and finding the intersect of their graphs shows that after about 6.64 hours, the bacteria will reach that number.

59a. Set the equation to 150,000 (the triple of 50,000) and solve it, so it’ll start off as 50,000(1+(0.075/4))^x=150,000. The answer will be about 59.1 years.
59b. Do the same as the last question, except with the equation 50,000e^(0.075•x). The answer will be about 14.6 years.

One number is 48 and the other number is 36.