Ireally dont understand will give 100 points

show !

circle with tangent mn.
msn = 60°; mqs = x; mqp = x + 40; m pn = 2x-16

find x =

angle 5 =

angle 1 =

angle 2 =

angle 6 =

angle 7 =

angle 3 =

angle 8 =

angle 4 =

mpn =

Part 1) The value of x is 69°

Part 2) Angle 1=64.5°

Part 3) Angle 2=84.5°

Part 4) Angle 3=31°

Part 5) Angle 4=84.5°

Part 6) Angle 5=95.5°

Part 7) Angle 6=95.5°

Part 8) Angle 7=54.5°

Part 9) Angle 8=30°

Step-by-step explanation:

Part 1) Find the value of x

we know that

arc SN+arc QS+arc QP+arc PN=360° > by complete circle

substitute the values

60°+x°+(x+40)°+(2x-16)°=360°

solve for x

84°+4x°=360°

4x=276°

x=69°

Part 2) Find the measure of angle 1

we know that

The inscribed angle is half that of the arc it comprises

so

m∠1=(1/2)[arc QSN]

arc QSN=arc QS+SN

arc QSN=x+60°=69°+60°=129°

substitute

m∠1=(1/2)[129°]=64.5°

Part 3) Find the measure of angle 2

we know that

The measure of the inner angle is the semi-sum of the arcs that comprise it and its opposite

m∠2=(1/2)[arc SN+arc QP]

substitute the values

m∠2=(1/2)[60°+(x+40)°]

m∠2=(1/2)[60°+(69+40)°]

m∠2=(1/2)[169°]=84.5°

Part 4) Find the measure of angle 3

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

m∠3=(1/2)[arc PN-arc SN]

substitute the values

m∠3=(1/2)[(2x-16)°-60°]

m∠3=(1/2)[(2(69)-16)°-60°]

m∠3=(1/2)[62°]=31°

Part 5) Find the measure of angle 4

we know that

m∠4=m∠2 > by vertical angles

so

m∠4=84.5°

Part 6) Find the measure of angle 5

we know that

m∠5+m∠2=180° > by supplementary angles

so

m∠5+84.5°=180°

m∠5=180°-84.5°=95.5°

Part 7) Find the measure of angle 6

we know that

m∠6=m∠5 > by vertical angles

so

m∠6=95.5°

Part 8) Find the measure of angle 7

we know that

The inscribed angle is half that of the arc it comprises

so

m∠7=(1/2)[arc QP]

arc QP=(x+40)°=(69+40)°=109°

substitute

m∠7=(1/2)[109°]=54.5°

Part 9) Find the measure of angle 8

we know that

The inscribed angle is half that of the arc it comprises

so

m∠8=(1/2)[arc SN]

arc SN=60°

substitute

m∠8=(1/2)[60°]=30°

Shania is correct.

Step-by-step explanation:

For a right angled triangle, given two sides and an angle, we can use the sine rule or the various trigonometry identities to solve the triangle;

a/sin A = b/sinB

and

sin (angle) = opposite side/hypotenuse

cos (angle) = adjacent side/hypotenuse

tan (angle) = opposite/ adjacent

assuming a is the opposite side of angle A and b is also opposite of angle B

Otherwise, the only way to solve a triangle given two sides only is by the use of the Pythagoras theorem.

Hence, Shania is correct.