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theodisb8440

13.06.2020

Mathematics

The probability that the person gets a speeding ticket is 0.27

Step-by-step explanation:

The probability that the person receives a speeding ticket is the probability that the person passes through any of the speed limits and the radar is operating at that time.

Let P(L_1) is the probability that the person passes through radar $L_{1}$ and it is operating at that time is

$P(L_{1})=P(1)\times P(2)$

Where

P(1) is the probability of person passes through $L_{1}$

P(2) is probability that the radar is operating

$P(L_1)=0.2\times 0.4=0.08$

Similarly the probabilities are calculated for other radars in the similar manner as

$P(L_2)=0.1\times 0.3=0.03$

$P(L_3)=0.5\times 0.2=0.1$

$P(L_4)=0.2\times 0.3=0.06$

Thus the reuired probability of the reuired event is

$P(E)=P(L_1)+P(L_2)+P(L_3)+P(L_4)\\\\P(E)=0.08+0.03+0.1+0.06=0.27$

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