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cooper2017
19.10.2019 •
Mathematics
Is (x+7) a factor of f(x)= x^3-3x^2+2x-8
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Ответ:
Since f(-7) ≠ 0, hence (x+7) is not a factor of f(x)= x³-3x²+2x-8
Polynomial is an expression involving the operations of addition, subtraction, multiplication of variables.
Types of polynomials are quadratic, linear, cubic and so on.
The factor theorem states that; when f(k) = 0, then (x – k) is a factor of f(x).
To determine if (x+7) a factor of f(x)= x^3-3x^2+2x-8, we:
x + 7 = 0
x = -7
f(-7) = (-7)³ - 3(-7)² + 2(-7) - 8 = -512
Since f(-7) ≠ 0, hence (x+7) is not a factor of f(x)= x³-3x²+2x-8
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Ответ:
Step-by-step explanation:
Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.
We use -7 as the divisor in synth. div. This comes from the factor (x + 7):
-7 / 1 3 2 -8
-7 28 -210
1 -4 30 -218
Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.
Ответ:
in decimal form its 15%