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kam3864
24.01.2021 •
Mathematics
Isabelle has $5.45 in her purse. If she has five more nickels than dimes, and twice as many quarters than dimes, how many of each type of coin does she have?
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Ответ:
Nickel = 13
Dimes = 8
Quarters = 16
Step-by-step explanation:
Let N denote Nickel,
Let D denote dime
Let Q denote quarter
Now, from online conversions;
1 nickel = 5 cents
Also, 1 dime = 10 cents
Also, 1 quarter = 25 cents
Isabelle has $5.45 which is also 545 cents.
Thus, we have;
5N + 10D + 25Q = 545 - - - (eq 1)
We are told that;
she has five more nickels than dimes, and twice as many quarters than dimes.
Thus;
N = D + 5
Also, Q = 2D
Plugging them for N and Q in eq 1 givens;
5(D +5) + 10D + 25(2D) = 545
5D + 25 + 10D + 50D = 545
25 + 65D = 545
65D = 545 - 25
65D = 520
D = 520/65
D = 8
Thus; N = D + 5 = 8 + 5 = 13
Q = 2D = 2 × 8 = 16
Ответ:
This question is not biased. Straight up fair for both items. Fresh this or fresh that.
-:)Jay