It is computed that when a basketball player shoots a free throw, the odds in favor of his making it are 2020 to 99. find the probability that when this basketball player shoots a free throw, he misses it. out of every 100 free throws he attempts, on the average how many should he make?

Step-by-step explanation:

Given that when a basketball player shoots a free throw, the odds in favor of his making it are 2020 to 99.

Prob that he shoots a free throw =

a) Probability that when this basketball player shoots a free throw, he misses it=1-0.04672 = 0.95328

b) When no of throws = 100 average of throws he makes is

Since x no of throws he makes has two outcomes and each trial is independent , X is binomial with n =100 and p = 0.04672

Expected value of throws = np = 4.672

m∠BEC + m∠CED = m∠BED; Angle Addition Postulate

Step-by-step explanation:

For example : If ∠MON and ∠NOK are joined such that NO is the common line segment between then then the new angle will be ∠MOK or ∠KOM.

In given figure , m∠BEC and m∠CED are joined and they have common line segment CE , then the new angle m∠BED= m∠BEC + m∠CED

Hence, the correct statement that completes the given proof :

m∠BEC + m∠CED = m∠BED; Angle Addition Postulate