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andreyvaught2754
19.08.2019 •
Mathematics
It is due i need with 9, 11, and 12
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Ответ:
So in 'y' years from the start, its size is modeled by the function
Population = (original size) x (1.02)^y power
This equation is familiar from all of the bank-interest problems.
9). The population is 765 right now. In 'y' more years from now, it will be
Population = 765 x (1.02)^y power
11). In 5 years from now, it will be P = 765 (1.02)^5 = 845 students (rounded)
12). The population will exceed 1,000 students when
1,001 = 765 (1.02)^y
Divide each side by 765 : 1,001/765 = (1.02)^y
Take the log of each side: log(1,001/765) = y log(1.02)
Divide each side by log(1.02) : y = log(1,001/765) / log(1.02)
Fire up your calculator and crank out that number:
log(1,001/765) / (log(1.02) = 0.11677 / 0.0086 = 13.5779 years
If the 2% growth is steady and uniform 24/7 throughout the year, then
this number means that the 1,001th student will enroll in
13 years 30 weeks 1 day 2 hours 6 minutes 36 seconds from right now.
Ответ:
2* (2x-10)= x - 8
2*2x - 2*10= x - 8
4x - 20= x - 8 | +20
4x = x + 20 - 8 = x + 12 | - x
4x - x = 12
3x = 12
x= 12:3
x= 4
y= 2*4 - 10
y= 8 - 10
y= - 2