It is known that a polynomial has solution if

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Rooster04

19.01.2022

(3) the polynomial has degree 3. If it were a complex coefficient polynomial, then the answer is 2.

Step-by-step explanation:

I am assuming it is a real coefficient polynomial, otherwise the answer will be 2. Since 3i is a root, then so is its conjugate -3i, therefore the polynomial is a multiple of (x-(-1)) *(x-3i) * (x-(-3i)) = (x+1) * (x²+9), which has real coefficients. Hence, its degree is atleast 3. Option (3) is correct

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Ответ:

hunterbetterton1

01.04.2022

Mathematics

Hot air balloon volume: density isgiven by the formula: $\text{density} = \dfrac{m}{v}$ with mass $m$ and volume $v$ .if you want to find the volume, we can make volume the subject of the density formula.multiply both sides by v so that the v in the denominator on the right side cancels out. $\begin{aligned} \text{density} \cdot v & = \dfrac{m}{v} \cdot v \\ \text{density} \cdot v & = m \end{aligned}$ divide both sides by density. $\begin{aligned} \text{density} \cdot v & = m \\ v & = \dfrac{m}{\text{density}} \end{aligned}$ mass divided by density will get you volume.you could also do this by dimensional analysis.e.g., balloon with volume of $600\text{ kg}$ and a density of $0.85 \text{ kg/m}^3$ . $0.85 \text{ kg/m}^3 = \dfrac{0.85\text{ kg}}{\text{m}^3} \iff \dfrac{\text{m}^3}{0.85\text{ kg}}$ this means that you want to cancel out the units. $600\text{ kg} \cdot \dfrac{\text{m}^3}{0.85\text{ kg}}$ the units of kg cancel out and you are left with 600m³/0.85, which is approx 706 m³it's the exact answer if you did as mass divided by density, just not as much memorizing. you just focus on canceling out units.======center and radius of circle from eqn: standard form of a circle: $(x-h)^2 + (y-k)^2 = r^2$ the center is at $(h,k)$ and radius is $r$ . if you rearrange equations of circles, you can identify using this form.e.g. for the circle $(x+3)^2 + (y-1)^2 = 49$ we can rewrite as $\begin{aligned} \big()\big)^2 + (y-1)^2 & = \left(\sqrt{49}\right)^2 \\ \big()\big)^2 + (y-1)^2 & = \left(7\right)^2 \\ \end{aligned}$ so h = -3, k = 1, and the radius is 7e.g. the circle $(x-2)^2+(y+3)^2=2$ has center at (2,-3) and radius of $\sqrt{2}$ . (2 can be written as $\left(\sqrt{2}\right)^2$ )======measure of angle in a quadrilateral angles in a quadrilateral all sum up to 360 degrees.if a quadrilateral has angles $\angle a$ , $\angle b$ , $\angle c$ and $\angle d$ , then $\angle a + \angle b + \angle c + \angle d = 360^{\circ}$ if the quadrilateral is inscribed in a circle, then angles in the quadrilateral opposite to each other sum to up 180 degrees.

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It is known that a polynomial has solution if -1 and 3i. What is the lowest possible degree polynomial with these solutions? (1) 1 (2) 2 (3) 3 (4) 4

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