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noahdeem135

26.03.2023

Mathematics

$N(t)=\dfrac{54}{0.35+0.68^t}$

The number of beavers initially introduced is the population at time t=0

, so you need to find N(0)

.

$N(0)=\dfrac{54}{0.35+0.68^0}=\dfrac{54}{1.35}=40$

The number of beavers after 5 years is given by N(5)

.

$N(5)=\dfrac{54}{0.35+0.68^5}\approx\dfrac{54}{0.495}\approx109$

The change in the beaver population between t=5

and

is simply the difference N(10)-N(5)

. Evaluate the function at these points (you already know N(5)

) and subtract. You should get approximately $36.49\approx36$ .

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It is not important to develop effective communication skills. Please select the best answer from the choices provided.