Ithink it’s a but again i’m not sure.

a) y = 6x - 3

b) 1/3y = 2x -1

The first thing you need to do is isolate (y) in the second equation

3 x (1/3y) = 3 x (2x - 1)

y =6x - 3

After isolating (y) in equation b they end up being the same.

Graphing:

In order to graph this, you have to make the first point at (0, -3) since this is the Y-intercept of the equation.

In order to graph the other points, you must move 6 units up and 1 unit to the right. Or vise versa If you need a visual I'll gladly link one.