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kekejones6321
28.01.2020 •
Mathematics
Iwill give brainliest for correct answer only if you explain how you got the answer
a plane is located at c on the diagram. there are two towers located at a and b. the distance between the towers is 7,600 feet, and the angles of elevation are given.
a. find bc, the distance from tower 2 to the plane, to the nearest foot.
b. find cd, the height of the plane from the ground, to the nearest foot.
wont let me comment or view comments on my questions right now but i will give you brainliest when it allows me)
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Ответ:
Let's assume CD=h, BD=x.
tan 24°=h/x ==>h=x*tan 24°
tan 16°=h/(7600+x)==>h=tan 16° *(7600+x)
==>x tan 24°=tan 16°*(7600+x)
==>x=(7600*tan 16°)/(tan 24°-tan 16°)
h=x*tan 24= (7600*tan 16°*tan 24°)/(tan 24°-tan16°)
b) CD=h=6122,2303...≈6122 (feet)
a) BC=h/sin 24°=15052,0746448...≈15052 (feet)
=
Ответ:
the answer is 1/5 for the probability