Jack crawled 4 ft and christine crawled 3⁄4 the distance jack crawled. if you add the distance they each crawled together, what is the total distance the two children crawled. (write the answer in inches.)

Before going into the details of the problem, let us first write down the most important information required for solving this problem.
1 ft = 12 inches
The distance that was crawled by Jack = 4 ft
                                                                = (4 * 12) inches
                                                                = 48 inches
The distance crawled by Christine = 3/4 of the distance crawled by Jack
                                                         = (3/4) * 48 inches
                                                         = 3 * 12 inches
                                                         = 36 inches
Then
The total distance crawled by the two children's = (48 + 36) inches
                                                                             = 84 inches
So Jack and Christine together crawled a distance of 84 inches.

Solution:

The two equation given which are in two variables are

1. y = x²-2 x -1 9

2. y + 4 x=5

Writing equation 2 as→y = 5 -4 x

Substituting the value of y in equation 1

⇒ 5 - 4 x = x² - 2 x - 19

⇒x² - 2 x + 4 x -19 -5=0

⇒ x² + 2 x -24=0

⇒x² + 6 x - 4 x - 24=0→→→[Breaking the middle term i.e term containing x]

⇒ x(x+6) -4(x+6)=0

⇒(x-4)(x+6)=0

⇒x-4=0 ∧ x+6=0

⇒x = 4     ∧    x= -6

Put x=4 in equation 2,

y + 4 ×4=5

y + 16=5

y = 5-16

y= -11

As one solution is (-6, 29), The other solution of the system of equation is (4, -11).