Jan's house has four leaking taps. An average of 34 cL of water leaks from each tap every day. How many litres of water is lost from these four taps in August?

42.16l

Step-by-step explanation:

First, we should note that August has 31 days. Since Jan's house has four leaking taps and an average of 34 cL of water leaks from each tap every day. The four taps will leak (34 × 4) = 136 cL everyday.

The amount of litres of water that is lost from these four taps in August would be:

= 136cL × 31

= 4216 cL

= 42.16L

We should note that 100cL = 1L

-9(-2/3)^{n-1}

Step-by-step explanation:

Given the sequence

-9,6,-4,8/3,-16/9

The sequence is a geometric progression. The nth term of a geometric progression is expressed as;

Tn = ar^{n-1}

a is the first term = -9

r is the common ratio = 6/-9 = -4/6 = -2/3

n is the number of terms

Substitute the given parameters into the formula;

Tn = -9(-2/3)^n-1

Hence the formula for the general term an of the sequence is  -9(-2/3)^{n-1}