Jane’s age is 5 years less than 3 times her brother’s age. jane’s age is 11 minus her brother’s age. how old is jane?

a) 3
b) 6
c) 7
d) 8

From the information given, Jane's age is 7 years.

Based on the information given, the first equation will be j = 3b - 5 while they second equation will be j = 11 - b.

Therefore, we'll equate both equations which will be:

3b - 5 = 11 - b

3b + b = 11 + 5

4b = 16

b = 16/4

b = 4.

Therefore, Jane's age will be:

j = 11 - b

j = 11 - 4

j = 7

James age is 7 years.

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ANSWER

C) 7

EXPLANATION

Let Jane's age be j, and his brother be b.

Jane’s age is 5 years less than 3 times her brother’s age.

Mathematically, we have;

j=3b-5(1)

Jane’s age is 11 minus her brother’s age.

This is also written mathematically as

j=11-b(2)

We equate the two equations to get;

11-b=3b-5

Group similar terms:

11+5=3b+b

16=4b

Divide both sides by 4:

b=4.

Therefore Jane's age is

11-4=7 years.

The correct answer is C.

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