Janice is asked to solve0=64x^2+16x-3 what is x

x=-1/8 or 3/8

Step-by-step explanation:

64x^2+16x-3=0

By Mid term breaking

64x^2-24x+8x-3=0

8x(8x-3)+1(8x-3)=0

(8x+1)(8x-3)=0

Either

8x+1=0 OR 8x-3=0

8x=-1 OR 8x=3

x=-1/8 OR x=3/8

limit of f(x) as x approaches 3 from the right side.

x= 3.1 results in 3

x= 3.01 results in 3

x= 3.001 results in 3

limit as x approaches 3 from the right side is 3.