Jason has three more peppers then he does cats if he has 11 pets know how many cats does he have

Consider the equation of an ellipse with coordinate axes as its major and minor axes: x^2/a^2 + y^2/b^2 = 1

Let a > b.
Here, a = 8/2 = 4 m and b = 2 m.
Hence, the equation becomes x^2/4^2 + y^2/2^2 = 1.
i.e. x^2/16 + y^2/4 = 1
i.e. x^2 + 4y^2 = 16 (1)

So we are required to find the ordinate of a point on the ellipse whose abscissa is a - 1.5 = 4 - 1.5 = 2.5 m.

So, put x = 2.5 in equation (1)
(5/2)^2 + 4y^2 = 16
25 + 16y^2 = 64
16y^2 = 39
y = √(39)/4, -√(39)/4

But since we are required to find height which is positive quantity so the required height of the point is √(39)/4 = 1.56 metres

1.56 Should be your answer.