yunilka28
14.02.2020 •
Mathematics
. Javier needs to exchange a dollar bill for
coins. The cashier has 2 quarters, 10
dimes and 10 nickels. We are asked to
determine how many possible
combinations of coins Javier could get
back if he must get back at least one of
the quarters.
Let’s start by assuming he uses only 1
quarter.
D N
7 1
6 3
5 5 That’s 5 combinations.
4 7
3 9
Now, assume he’s going to get both
quarters.
Solved
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Ответ:
11 Combination of Coins
Step-by-step explanation:
You've answered part of the question already.
I'll continue from where you stopped.
Let D represents Dime
Let N represents Nickels
The answer starts from here
Let’s start by assuming he uses only 1
quarter.
D N
7 1
6 3
5 5
4 7
3 9
That’s 5 combinations.
Notice that the sum of each row is a consecutive number.
i.e 8,9,10...
Now, let's assume he's going to get both quarters.
For Dime,he has 10/2 possible dime for a start.
For nickel, we'll start from the least possible; 0
While Dime reduces by 1, Nickel increases by 2
So, we have
D N
5 0
4 2
3 4
2 6
1 8
0 10
That's 6 combinations
Total Possible Combination = 5 + 6
Total Possible Combination = 11 Combinations
Ответ:
A. No Solution
Step-by-step explanation: