Mathematics: Jeanne traced her coffee mug on her piece of paper. how might she use paper-folding to find the center of the circle?

Jeanne traced her coffee mug on her piece of paper.

Weirddobby3964

28.08.2020

The probability of the widget weights lie between 43 and 87 ounces

P(43 ≤ x ≤ 87 ) = 0.7605

The percentage of the widget weights lie between 43 and 87 ounces

P(43 ≤ x ≤ 87 ) = 76 %

Step-by-step explanation:

Step(i):-

Given mean of the Population = 50ounces

Given standard deviation of the Population = 10 ounces

Let 'X' be the random variable in Normal distribution

Given X = 43

$Z = \frac{x-mean}{S.D} = \frac{43-50}{10} = -0.7$

Given X = 87

$Z = \frac{x-mean}{S.D} = \frac{87-50}{10} = 3.7$

Step(ii):-

The probability of the widget weights lie between 43 and 87 ounces

$P(43 \leq x\leq 87 ) = P(-0.7\leq z\leq 3.7 )$

= |A(3.7) + A(-0.7)|

= |A(3.7) + A(0.7)| (∵A(-z) = A(z))

= 0.4994 + 0.2611

= 0.7605

Final -

The probability of the widget weights lie between 43 and 87 ounces

P(43 ≤ x ≤ 87 ) = 0.7605

The percentage of the widget weights lie between 43 and 87 ounces

P(43 ≤ x ≤ 87 ) = 76 %

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