dozsyerra
12.07.2019 •
Mathematics
Jim weighs more than joe but less than jack. their weights in kilograms are consecutive by multiples of 7. if they each weighed 5kg less, the sum of their weights is 195kg
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Ответ:
Joe: 7k
Jim: 7(k+1)
Jack: 7(k+2)
(7k-5) + (7(k+1) - 5) + (7(k+2) - 5) = 195
(7k-5) + (7k+2) + (7k +9) = 195
21k + 6 = 195
21k = 189
k = 9
Joe: 7k = 7(9) = 63
Jim: 7(k+1) = 7(9+1) = 7(10) = 70
Jack: 7(k+2) = 7(9+2) = 7(11) = 77
Joe=63kg, Jim=70kg, Jack=77kg
Ответ: